Integrand size = 14, antiderivative size = 102 \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\frac {2 b^2}{27 x^3}+\frac {4 b^2 c^2}{9 x}+\frac {4}{9} b c^3 \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )+\frac {2 b c \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )}{9 x^2}-\frac {\left (a+b \sec ^{-1}(c x)\right )^2}{3 x^3} \]
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Time = 0.07 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {5330, 4490, 3391, 3377, 2718} \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\frac {2 b c \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )}{9 x^2}+\frac {4}{9} b c^3 \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )-\frac {\left (a+b \sec ^{-1}(c x)\right )^2}{3 x^3}+\frac {4 b^2 c^2}{9 x}+\frac {2 b^2}{27 x^3} \]
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Rule 2718
Rule 3377
Rule 3391
Rule 4490
Rule 5330
Rubi steps \begin{align*} \text {integral}& = c^3 \text {Subst}\left (\int (a+b x)^2 \cos ^2(x) \sin (x) \, dx,x,\sec ^{-1}(c x)\right ) \\ & = -\frac {\left (a+b \sec ^{-1}(c x)\right )^2}{3 x^3}+\frac {1}{3} \left (2 b c^3\right ) \text {Subst}\left (\int (a+b x) \cos ^3(x) \, dx,x,\sec ^{-1}(c x)\right ) \\ & = \frac {2 b^2}{27 x^3}+\frac {2 b c \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )}{9 x^2}-\frac {\left (a+b \sec ^{-1}(c x)\right )^2}{3 x^3}+\frac {1}{9} \left (4 b c^3\right ) \text {Subst}\left (\int (a+b x) \cos (x) \, dx,x,\sec ^{-1}(c x)\right ) \\ & = \frac {2 b^2}{27 x^3}+\frac {4}{9} b c^3 \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )+\frac {2 b c \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )}{9 x^2}-\frac {\left (a+b \sec ^{-1}(c x)\right )^2}{3 x^3}-\frac {1}{9} \left (4 b^2 c^3\right ) \text {Subst}\left (\int \sin (x) \, dx,x,\sec ^{-1}(c x)\right ) \\ & = \frac {2 b^2}{27 x^3}+\frac {4 b^2 c^2}{9 x}+\frac {4}{9} b c^3 \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )+\frac {2 b c \sqrt {1-\frac {1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )}{9 x^2}-\frac {\left (a+b \sec ^{-1}(c x)\right )^2}{3 x^3} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.06 \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\frac {-9 a^2+6 a b c \sqrt {1-\frac {1}{c^2 x^2}} x \left (1+2 c^2 x^2\right )+2 b^2 \left (1+6 c^2 x^2\right )+6 b \left (-3 a+b c \sqrt {1-\frac {1}{c^2 x^2}} x \left (1+2 c^2 x^2\right )\right ) \sec ^{-1}(c x)-9 b^2 \sec ^{-1}(c x)^2}{27 x^3} \]
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Time = 0.90 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.50
method | result | size |
parts | \(-\frac {a^{2}}{3 x^{3}}+b^{2} c^{3} \left (-\frac {\operatorname {arcsec}\left (c x \right )^{2}}{3 c^{3} x^{3}}+\frac {2 \,\operatorname {arcsec}\left (c x \right ) \left (2 c^{2} x^{2}+1\right ) \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}}{9 c^{2} x^{2}}+\frac {2}{27 c^{3} x^{3}}+\frac {4}{9 c x}\right )+2 a b \,c^{3} \left (-\frac {\operatorname {arcsec}\left (c x \right )}{3 c^{3} x^{3}}+\frac {\left (c^{2} x^{2}-1\right ) \left (2 c^{2} x^{2}+1\right )}{9 \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}\, c^{4} x^{4}}\right )\) | \(153\) |
derivativedivides | \(c^{3} \left (-\frac {a^{2}}{3 c^{3} x^{3}}+b^{2} \left (-\frac {\operatorname {arcsec}\left (c x \right )^{2}}{3 c^{3} x^{3}}+\frac {2 \,\operatorname {arcsec}\left (c x \right ) \left (2 c^{2} x^{2}+1\right ) \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}}{9 c^{2} x^{2}}+\frac {2}{27 c^{3} x^{3}}+\frac {4}{9 c x}\right )+2 a b \left (-\frac {\operatorname {arcsec}\left (c x \right )}{3 c^{3} x^{3}}+\frac {\left (c^{2} x^{2}-1\right ) \left (2 c^{2} x^{2}+1\right )}{9 \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}\, c^{4} x^{4}}\right )\right )\) | \(154\) |
default | \(c^{3} \left (-\frac {a^{2}}{3 c^{3} x^{3}}+b^{2} \left (-\frac {\operatorname {arcsec}\left (c x \right )^{2}}{3 c^{3} x^{3}}+\frac {2 \,\operatorname {arcsec}\left (c x \right ) \left (2 c^{2} x^{2}+1\right ) \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}}{9 c^{2} x^{2}}+\frac {2}{27 c^{3} x^{3}}+\frac {4}{9 c x}\right )+2 a b \left (-\frac {\operatorname {arcsec}\left (c x \right )}{3 c^{3} x^{3}}+\frac {\left (c^{2} x^{2}-1\right ) \left (2 c^{2} x^{2}+1\right )}{9 \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}\, c^{4} x^{4}}\right )\right )\) | \(154\) |
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Time = 0.28 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.91 \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\frac {12 \, b^{2} c^{2} x^{2} - 9 \, b^{2} \operatorname {arcsec}\left (c x\right )^{2} - 18 \, a b \operatorname {arcsec}\left (c x\right ) - 9 \, a^{2} + 2 \, b^{2} + 6 \, {\left (2 \, a b c^{2} x^{2} + a b + {\left (2 \, b^{2} c^{2} x^{2} + b^{2}\right )} \operatorname {arcsec}\left (c x\right )\right )} \sqrt {c^{2} x^{2} - 1}}{27 \, x^{3}} \]
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\[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\int \frac {\left (a + b \operatorname {asec}{\left (c x \right )}\right )^{2}}{x^{4}}\, dx \]
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Time = 0.46 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.61 \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=-\frac {2}{9} \, a b {\left (\frac {c^{4} {\left (-\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {3}{2}} - 3 \, c^{4} \sqrt {-\frac {1}{c^{2} x^{2}} + 1}}{c} + \frac {3 \, \operatorname {arcsec}\left (c x\right )}{x^{3}}\right )} - \frac {b^{2} \operatorname {arcsec}\left (c x\right )^{2}}{3 \, x^{3}} - \frac {a^{2}}{3 \, x^{3}} + \frac {2 \, {\left ({\left (6 \, c^{3} x^{2} + c\right )} \sqrt {c x + 1} \sqrt {c x - 1} + 3 \, {\left (2 \, c^{5} x^{4} - c^{3} x^{2} - c\right )} \arctan \left (\sqrt {c x + 1} \sqrt {c x - 1}\right )\right )} b^{2}}{27 \, \sqrt {c x + 1} \sqrt {c x - 1} c x^{3}} \]
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Time = 0.30 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.65 \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\frac {1}{27} \, {\left (12 \, b^{2} c^{2} \sqrt {-\frac {1}{c^{2} x^{2}} + 1} \arccos \left (\frac {1}{c x}\right ) + 12 \, a b c^{2} \sqrt {-\frac {1}{c^{2} x^{2}} + 1} + \frac {12 \, b^{2} c}{x} + \frac {6 \, b^{2} \sqrt {-\frac {1}{c^{2} x^{2}} + 1} \arccos \left (\frac {1}{c x}\right )}{x^{2}} + \frac {6 \, a b \sqrt {-\frac {1}{c^{2} x^{2}} + 1}}{x^{2}} - \frac {9 \, b^{2} \arccos \left (\frac {1}{c x}\right )^{2}}{c x^{3}} - \frac {18 \, a b \arccos \left (\frac {1}{c x}\right )}{c x^{3}} - \frac {9 \, a^{2}}{c x^{3}} + \frac {2 \, b^{2}}{c x^{3}}\right )} c \]
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Timed out. \[ \int \frac {\left (a+b \sec ^{-1}(c x)\right )^2}{x^4} \, dx=\int \frac {{\left (a+b\,\mathrm {acos}\left (\frac {1}{c\,x}\right )\right )}^2}{x^4} \,d x \]
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